The initial water volume in this container was 10.0 mL. When the key was submerged, 3 volumes of displaced water were collected: 0.7 mL, 0.8 mL, and 0.9 mL. What is the volume of the key?
mL
To find the volume of the key, we need to subtract the volumes of the displaced water from the initial water volume.
Volume of key = Initial water volume - Volume of displaced water
= 10.0 mL - (0.7 mL + 0.8 mL + 0.9 mL)
= 10.0 mL - 2.4 mL
= 7.6 mL
Therefore, the volume of the key is 7.6 mL.
To find the volume of the key, we need to subtract the volumes of displaced water from the initial water volume.
Initial water volume = 10.0 mL
Volume of first displaced water = 0.7 mL
Volume of second displaced water = 0.8 mL
Volume of third displaced water = 0.9 mL
Total volume of displaced water = 0.7 mL + 0.8 mL + 0.9 mL = 2.4 mL
Volume of the key = Initial water volume - Total volume of displaced water
Volume of the key = 10.0 mL - 2.4 mL
Volume of the key = 7.6 mL
Therefore, the volume of the key is 7.6 mL.