Make t the subject of formula S = ut + 1/2at2
A. 1a (-u + U2−2as−−−−−−−−√)
B. 1a {u ± (U2 - 2as)}
C. 1a {u ± 2as−−−√}
D. 1a {-u + (2as)−−−−√}
To make t the subject of the formula S = ut + 1/2at^2, we need to isolate t on one side of the equation.
First, let's subtract ut from both sides of the equation to get rid of it on the right side:
S - ut = (1/2)at^2
Next, let's multiply both sides of the equation by 2 to get rid of the fraction:
2(S - ut) = at^2
Expanding the bracket on the left side:
2S - 2ut = at^2
Now, let's rearrange the equation to solve for t:
2ut = 2S - at^2
Divide both sides of the equation by 2u:
t = (2S - at^2) / (2u)
This can also be written as:
t = (S - (1/2)at^2) / u
Therefore, the correct answer is option A: 1a (-u + U2−2as−−−−−−−−√)
To make t the subject of the formula S = ut + 1/2at^2, we can follow these steps:
Step 1: Start with the equation S = ut + 1/2at^2.
Step 2: Subtract ut from both sides of the equation to isolate the term involving t.
S - ut = 1/2at^2.
Step 3: Multiply both sides of the equation by 2 to eliminate the fraction.
2(S - ut) = 2(1/2at^2).
2S - 2ut = at^2.
Step 4: Rearrange the equation to isolate t^2 on one side.
at^2 = 2S - 2ut.
Step 5: Divide both sides of the equation by a to isolate t^2.
t^2 = (2S - 2ut) / a.
Step 6: Take the square root of both sides to solve for t.
t = ± √[(2S - 2ut) / a].
Therefore, the correct answer is option B. 1a {u ± (U2 - 2as)}.