41. Calculate the force acting on
an electron of charge 1.6 x 10-19C
placed in an electric field intensity
108Vm−1
.
A. 1.6 x 10−11N
B. 1.6 x 10−14N
C. 1.6 x 10−16N
To calculate the force acting on an electron in an electric field, we can use the formula:
F = qE
where F is the force, q is the charge of the electron, and E is the electric field intensity.
Given that the charge of the electron (q) is 1.6 x 10^-19 C and the electric field intensity (E) is 1.08 x 10^8 V/m, we can substitute these values into the formula to find the force:
F = (1.6 x 10^-19 C)(1.08 x 10^8 V/m)
F = 1.728 x 10^-11 N
Therefore, the force acting on the electron is 1.728 x 10^-11 N. Rounding this to two significant figures, the answer is approximately 1.7 x 10^-11 N.
So, the correct answer is:
A. 1.6 x 10^-11 N
To calculate the force acting on an electron in an electric field, we can use the formula:
F = qE
where F is the force, q is the charge of the electron, and E is the electric field intensity.
Given:
Charge of electron (q) = 1.6 x 10^(-19) C
Electric field intensity (E) = 108 V/m
Substituting the values into the formula, we get:
F = (1.6 x 10^(-19) C) * (108 V/m)
Now let's calculate the force:
F = 1.6 x 10^(-19) C * 108 V/m
F = 1.728 x 10^(-17) N
Therefore, the force acting on the electron is 1.728 x 10^(-17) N.
None of the given options match this result.