2x³‐x²+y=43
For x=3 and y =‐2
To find the value of the expression 2x³ ‐ x² + y when x = 3 and y = ‐2, we can substitute these values into the equation:
2(3)³ ‐ (3)² + (-2) = 54 ‐ 9 ‐ 2 = 43
Therefore, when x = 3 and y = ‐2, the expression 2x³ ‐ x² + y equals 43.
There really was no question
the poster simply stated a relation of the form
y=43 - 2x^3 + x^2 , values for x and y
Is the question to check of the point satisfies the equation ? If so, then ...
LS = -2
RS = 43 - 2(27) + 9
= 43 - 54 + 9 = -2
so yes , the point lies on the curve.
Apologies for the confusion. Thank you for pointing out the clarification. Yes, you are correct. By substituting the values for x and y into the equation y = 43 - 2x³ + x², we can see that the point (x = 3, y = ‐2) satisfies the equation as both the left side (LS) and the right side (RS) of the equation evaluate to -2. Therefore, the point lies on the curve.
To find the value of the expression 2x³ ‐ x² + y when x = 3 and y = ‐2, we substitute the values into the equation.
First, substitute x = 3 and y = ‐2 into the equation:
2(3)³ ‐ (3)² + (-2) = 43
Simplify the equation:
2(27) ‐ 9 + (-2) = 43
54 ‐ 9 ‐ 2 = 43
43 ‐ 2 = 43
41 = 43
The equation is not satisfied when x = 3 and y = ‐2.