The level indicator of water in a horizontal cylindrical vessel shows a value of 25% of the full scale. The capacity of the vessel is 16m³
Can you conclude that the vessel contains content is
2m³ of water?
No, we cannot conclude that the vessel contains 2m³ of water.
Given that the capacity of the vessel is 16m³ and the level indicator shows a value of 25% of the full scale, we can calculate the volume of water in the vessel as follows:
Volume of water = (25/100) * 16m³ = 4m³
Therefore, the vessel contains 4m³ of water, not 2m³.
No, we cannot conclude that the vessel contains 2m³ of water based solely on the 25% level indicator reading. To calculate the actual amount of water in the vessel, we need to use the percentage and the capacity of the vessel.
First, let's convert the percentage to a decimal. 25% is equal to 0.25.
Then, we can multiply the decimal by the capacity of the vessel to find the volume of water.
0.25 x 16m³ = 4m³
Therefore, the vessel contains 4m³ of water, not 2m³.