20,0g MgCl2 and 20,0g NaCl are mixed together and dissolved in water to make up 2,00dm cube of solution. Calculate the concentration of the chloride ions in the solution
To calculate the concentration of chloride ions in the solution, we need to determine the moles of chloride ions present in the solution first.
First, let's calculate the moles of MgCl2:
Molar mass of MgCl2 = 24.305 g/mol + 2 * 35.453 g/mol = 95.211 g/mol
Moles of MgCl2 = 20.0 g / 95.211 g/mol = 0.20990 mol
Next, let's calculate the moles of NaCl:
Molar mass of NaCl = 22.990 g/mol + 35.453 g/mol = 58.443 g/mol
Moles of NaCl = 20.0 g / 58.443 g/mol = 0.342019 mol
Now, let's calculate the total moles of chloride ions in the solution:
Total moles of chloride ions = 2 * (0.20990 mol + 0.342019 mol) = 1.103818 mol
Finally, let's calculate the concentration of chloride ions in the solution:
Concentration (mol/dm^3) = Total moles of chloride ions / Volume of solution
Concentration (mol/dm^3) = 1.103818 mol / 2.00 dm^3
Concentration (mol/dm^3) ≈ 0.5519 mol/dm^3
Therefore, the concentration of the chloride ions in the solution is approximately 0.5519 mol/dm^3.
To calculate the concentration of chloride ions in the solution, we need to determine the moles of chloride ions present and then divide by the volume of the solution.
First, let's calculate the number of moles of MgCl2 and NaCl:
Molar mass of MgCl2 = atomic mass of Mg + 2 * atomic mass of Cl
= 24.31 g/mol + 2 * 35.45 g/mol
= 95.21 g/mol
Molar mass of NaCl = atomic mass of Na + atomic mass of Cl
= 22.99 g/mol + 35.45 g/mol
= 58.44 g/mol
Moles of MgCl2 = mass of MgCl2 / molar mass of MgCl2
= 20.0 g / 95.21 g/mol
= 0.210 moles
Moles of NaCl = mass of NaCl / molar mass of NaCl
= 20.0 g / 58.44 g/mol
= 0.342 moles
Next, let's calculate the total moles of chloride ions present:
Total moles of chloride ions = 2 * (moles of MgCl2 + moles of NaCl)
= 2 * (0.210 moles + 0.342 moles)
= 0.904 moles
Finally, let's calculate the concentration of chloride ions:
Concentration of chloride ions = moles of chloride ions / volume of solution
= 0.904 moles / 2.00 dm^3
= 0.452 mol/dm^3
Therefore, the concentration of chloride ions in the solution is 0.452 mol/dm^3.