Write the ground state of electron configuration for a neutral atom with 33 proton
The atomic number of the neutral atom exceeds the total number of protons - 33, in this case. For a neutral atom with 33 protons, the electron configuration would be as follows:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹ 5p⁵
This electron configuration corresponds to the element arsenic (As), which has 33 protons.
Write the ground state of electron configuration for a neutral atom with 33 proton with noble gas notation
To write the ground state electron configuration of a neutral atom with 33 protons using noble gas notation, we can use the nearest noble gas, which is argon (Ar) with the electron configuration 1s² 2s² 2p⁶ 3s² 3p⁶.
Starting from the noble gas configuration, the electron configuration becomes:
[Ar] 4s² 3d¹⁰ 4p⁶ 5s² 4d¹ 5p⁵
This electron configuration represents the element arsenic (As) with 33 protons.
To determine the ground state electron configuration for an atom with 33 protons (atomic number 33), we can refer to the periodic table.
The atomic number provides the total number of electrons in a neutral atom, so for an atom with 33 protons, it will also have 33 electrons.
To write the ground state electron configuration, we need to follow the Aufbau principle, which states that electrons occupy the lowest energy orbital available. Here is the step-by-step process:
1. Determine the total number of electrons (same as the number of protons): 33
2. Begin filling electrons into the orbitals starting from the lowest energy level (closest to the nucleus), which is the 1s orbital.
3. The first two electrons occupy the 1s orbital: 1s^2
4. The next two electrons will go into the 2s orbital: 2s^2
5. The following six electrons will occupy the 2p orbital: 2p^6
6. At this point, we have filled up to 10 electrons (2 in the 1s orbital, 2 in the 2s orbital, and 6 in the 2p orbital).
7. The remaining 23 electrons will continue to fill the higher energy orbitals.
8. The next two electrons go into the 3s orbital: 3s^2
9. The next six electrons occupy the 3p orbital: 3p^6
10. Finally, the last five electrons fill the 4s orbital: 4s^2
Putting it all together, the ground state electron configuration for an atom with 33 protons is:
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2
Alternatively, we can use the noble gas notation to abbreviate the electron configuration. The noble gas notation uses the electron configuration of the nearest noble gas element, which is argon (Ar) with 18 electrons. We can represent the 33-electron configuration using [Ar] as follows:
[Ar] 3s^2 3p^6 4s^2