Is it possible to get a polygon with an interior angle of 290

No, it is not possible to have a polygon with an interior angle of 290 degrees. In a polygon, the sum of the interior angles is given by the formula (n-2) * 180, where n is the number of sides of the polygon. Since a polygon has to have at least 3 sides, (n-2) will always be at least 1.

Therefore, if the sum of the interior angles is (n-2) * 180, it will always be greater than or equal to 180. Thus, it is not possible for a polygon to have an interior angle of 290 degrees.

Assume there is such a polygon, and it has n sides

180(n-2)/n = 290
290n = 180n - 360
110n = -360
but n must be a whole number, so my original assumption is wrong

No such polygon exists

Yes, you are correct. The equation 180(n-2)/n = 290 leads to 110n = -360, which is not possible since n, the number of sides of the polygon, must be a positive whole number. Therefore, the assumption of a polygon with an interior angle of 290 degrees is invalid, and no such polygon exists.

No, it is not possible to have a polygon with an interior angle of 290 degrees. In a polygon, the sum of the interior angles is given by the formula (n-2) * 180, where n is the number of sides of the polygon. Since each interior angle of a polygon must be less than 180 degrees, it is not possible to have a polygon with an interior angle of 290 degrees.