In baseball, each time a player attempts to hit the ball, it is recorded. The ratio of hits compared to total attempts is their batting average. Each player on the team wants to have the highest batting average to help their team the most. For the season so far, Jana has hit the ball 7 times out of 10 attempts. Tasha has hit the ball 10 times out of 16 attempts. Which player has a ratio that means they have a better batting average?
Tasha, because she has the lowest ratio since 0.7 < 0.625
Tasha, because she has the highest ratio since 56 over 80 is greater than 50 over 80
Jana, because she has the highest ratio since 56 over 80 is greater than 50 over 80
Jana, because she has the lowest ratio since 0.7 < 0.625
To compare the batting averages of Jana and Tasha, we need to calculate their ratios.
For Jana, the ratio of hits to total attempts is 7/10 = 0.7.
For Tasha, the ratio of hits to total attempts is 10/16 = 0.625.
Comparing the ratios, we can see that Jana has a higher ratio than Tasha: 0.7 > 0.625.
Therefore, Jana has a better batting average. So the correct answer is:
Jana, because she has the highest ratio since 0.7 > 0.625
To determine which player has a better batting average, we need to compare their ratios of hits to total attempts.
Jana has hit the ball 7 times out of 10 attempts, which can be written as a ratio of 7/10.
Tasha has hit the ball 10 times out of 16 attempts, which can be written as a ratio of 10/16.
To compare these ratios, we can simplify them to their simplest form:
Jana's ratio simplifies to 7/10.
Tasha's ratio simplifies to 5/8.
Comparing these simplified fractions, we can see that Jana's ratio of 7/10 is greater than Tasha's ratio of 5/8.
Therefore, the correct answer is: Jana, because she has the highest ratio since 7/10 is greater than 5/8.