Second harmonic motion of a string 1.5m long fixed at both ends 80HZ.The speed of transverse wave in the string is
To find the speed of the transverse wave in the string, we can use the formula:
v = λ * f,
where v is the speed of the wave, λ is the wavelength, and f is the frequency.
In this case, the length of the string is 1.5m and the frequency is 80Hz. Since the string is fixed at both ends, only half a wavelength fits on the string. Therefore, the wavelength is equal to twice the length of the string, or 2 * 1.5m = 3m.
Plugging in the values into the formula, we get:
v = 3m * 80Hz = 240 m/s.
Therefore, the speed of the transverse wave in the string is 240 m/s.
To find the speed of a transverse wave in a string, we can use the formula:
v = fλ
where:
v is the speed of the wave,
f is the frequency of the wave, and
λ is the wavelength of the wave.
In this case, we are given that the frequency is 80 Hz. To find the wavelength, we can use the formula for the wavelength of a standing wave on a string fixed at both ends, which is given by:
λ = 2L/n
where:
L is the length of the string, and
n is the harmonic number.
In this case, we are given that the string is 1.5 m long, and we want to find the speed of the wave for the second harmonic (n = 2). Plugging in these values into the formula, we get:
λ = 2(1.5 m)/2 = 1.5 m
Now we can plug the frequency (f) and wavelength (λ) into the formula for wave speed (v):
v = fλ = (80 Hz)(1.5 m) = 120 m/s
So, the speed of the transverse wave in the string is 120 m/s.