Write oxidation state to the following atom
a.CO2
b.SF6
c.MnO4^-
a. Carbon (C) in CO2 has an oxidation state of +4.
b. Sulfur (S) in SF6 has an oxidation state of +6.
c. Manganese (Mn) in MnO4^- has an oxidation state of +7.
a. In CO2, the oxidation state of carbon (C) is +4. Oxygen (O) has an oxidation state of -2. Therefore, the oxidation state of each oxygen atom is -2, and since there are two oxygen atoms, the total oxidation state of carbon would be +4 to balance the charge.
b. In SF6, the oxidation state of sulfur (S) can be calculated by first determining the oxidation state of fluorine (F). Fluorine always has an oxidation state of -1 in compounds. Since there are six fluorine atoms in SF6, the total oxidation state of fluorine is -6. To balance the charge, the oxidation state of sulfur is +6.
c. In MnO4^-, the oxidation state of oxygen (O) is -2. Since there are four oxygen atoms, the total oxidation state due to oxygen is -8. To balance the charge, the oxidation state of manganese (Mn) would be +7.