en three capacitors 0.3uF, 0.5 uF and 0.2 uF,
the joint capacitance when arranged to give
minimum capacitance is
A. 0.3uF
B. 1.0uF
C. 0.1uF
D. 0.5uF
To arrange the capacitors to give minimum capacitance, they should be connected in parallel. The formula for calculating the total capacitance when capacitors are connected in parallel is:
C_total = C1 + C2 + C3
Plugging in the values given:
C_total = 0.3uF + 0.5uF + 0.2uF
C_total = 1.0uF
Therefore, the joint capacitance when arranged to give minimum capacitance is 1.0uF.
Answer: B. 1.0uF
To determine the joint capacitance when the capacitors are arranged to give minimum capacitance, we need to find the equivalent capacitance in parallel.
To calculate the equivalent capacitance in parallel, we can use the following formula:
1/Ceq = 1/C1 + 1/C2 + 1/C3
Plugging in the values, we get:
1/Ceq = 1/0.3 + 1/0.5 + 1/0.2
Simplifying the equation gives:
1/Ceq = (10/3 + 2 + 5)
1/Ceq = 10/3 + 2 + 5
1/Ceq = 10/3 + 6/3 + 15/3
1/Ceq = 31/3
Taking the reciprocal of both sides to find Ceq:
Ceq = 3/31
Therefore, the joint capacitance when arranged to give minimum capacitance is approximately 0.097 uF or 0.1 uF (rounded).
So, the correct answer is C. 0.1 uF.