Consider a standard deck of 52
playing cards with 4
suits.
What is the probability of randomly drawing 1
card that is both a red card and a face card?
(Remember that face cards are jacks, queens, and kings.)
Enter your answer as a fraction in simplest form, using the / symbol, like this: 5/14
There are a total of 13 face cards in a deck (4 jacks, 4 queens, and 4 kings). Out of these 13 face cards, there are 6 red face cards (2 red jacks, 2 red queens, and 2 red kings).
The probability of randomly drawing a red face card is therefore 6 red face cards out of 52 total cards.
So the probability is 6/52, which simplifies to 3/26.
como se escribe ciento cincuenta mill en numeros?
El número "ciento cincuenta mil" se escribe como 150,000.
To find the probability of randomly drawing a card that is both a red card and a face card, we need to determine the number of cards that meet both conditions and divide it by the total number of cards in the deck.
There are 2 red suits (hearts and diamonds), and each has 3 face cards (jack, queen, and king). So, the number of red face cards is 2 * 3 = 6.
The total number of cards in the deck is 52.
Therefore, the probability of drawing a red card and a face card is 6/52.
Simplifying the fraction by dividing both the numerator and denominator by their greatest common divisor, we have:
6/52 = 3/26
So, the probability of randomly drawing a card that is both a red card and a face card is 3/26.
To find the probability of randomly drawing one card that is both a red card and a face card, we need to determine the number of favorable outcomes (cards that are both red and face cards) and the total number of possible outcomes (all cards in the deck).
First, let's calculate the number of favorable outcomes:
There are 2 red suits in a deck of 4 suits, which means there are 2 red face cards in each suit (King and Queen).
Since there are 2 red suits (hearts and diamonds), the total number of red face cards is 2 * 2 = 4.
Next, let's calculate the total number of possible outcomes:
There are 3 face cards in each suit (King, Queen, and Jack).
Since there are 4 suits, the total number of face cards is 3 * 4 = 12.
Therefore, the favorable outcomes are 4 and the total possible outcomes are 12.
Finally, we can calculate the probability:
Probability = Favorable outcomes / Total possible outcomes
= 4 / 12
= 1 / 3
So, the probability of randomly drawing one card that is both a red card and a face card is 1/3.