An 80.0-kg passenger in an SUV traveling at
is wearing a seat belt. The driver slams on the brakes and the SUV stops in
. Find the force of the seat belt on the passenger.
To find the force of the seat belt on the passenger, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass of passenger (m) = 80.0 kg
Acceleration (a) = ? (not provided)
However, we are not given the acceleration directly. Without that information, we cannot calculate the force accurately. Could you please provide the value for acceleration?
To find the force of the seat belt on the passenger, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the acceleration is the deceleration of the SUV when it stops abruptly.
Given:
Mass of the passenger (m) = 80.0 kg
Acceleration (a) = ?
To find the acceleration, we need to know the stopping time (t) or the stopping distance (d). Could you please provide the missing information?