The length of a rectangle is 3 times its width. If the perimeter of the rectangle is 11 cm, find its width.
Let's assume that the width of the rectangle is "w" cm.
If the length is 3 times the width, then the length would be 3w cm.
The perimeter of a rectangle can be found by adding all its sides, so:
Perimeter = 2(length + width)
So, in this case, the perimeter would be: 11 = 2(3w + w)
Now, let's solve for 'w':
11 = 2(4w)
Divide each side by 2:
11/2 = 4w/2
5.5 = 2w
Divide each side by 2:
5.5/2 = w
w = <<5.5/2=2.75>>2.75 cm. Answer: \boxed{2.75}.
Let's assume that the width of the rectangle is represented by "w" cm.
According to the given information, the length of the rectangle would then be 3w cm.
The formula for the perimeter of a rectangle is: 2(length + width).
Therefore, for this rectangle, the perimeter can be represented as: 2(3w + w).
We are given that the perimeter of the rectangle is 11 cm. So, we can equate this value to the above expression:
2(3w + w) = 11
Now, let's solve this equation step-by-step to find the value of "w", the width of the rectangle.
2(4w) = 11
8w = 11
w = 11/8
Therefore, the width of the rectangle is 11/8 cm.