the number of atoms of oxygen present in 11.2 l of ozone at ntp are
To determine the number of atoms of oxygen present in 11.2 L of ozone at NTP (Normal Temperature and Pressure), we need to calculate the number of moles of ozone and then multiply it by the Avogadro's number to get the number of atoms.
The molar volume of a gas at NTP is 22.4 L/mol.
First, let's calculate the number of moles of ozone:
11.2 L of ozone / 22.4 L/mol = 0.5 mol of ozone
Ozone (O3) has three oxygen atoms.
Number of atoms of oxygen in 0.5 mol of ozone = 0.5 mol x 3 atoms/mol = 1.5 mol
Now, we will multiply the number of moles of oxygen by Avogadro's number (6.022 x 10^23 atoms/mol) to get the number of atoms:
1.5 mol x 6.022 x 10^23 atoms/mol = 9.033 x 10^23 atoms of oxygen
Therefore, there are approximately 9.033 x 10^23 atoms of oxygen present in 11.2 L of ozone at NTP.
To determine the number of atoms of oxygen present in 11.2 L of ozone at NTP (Normal Temperature and Pressure), we need to follow a step-by-step approach:
Step 1: Find the molar volume of gas at NTP.
The molar volume of gas at NTP is approximately 22.4 L/mol.
Step 2: Determine the number of moles of ozone present.
Given the volume of ozone as 11.2 L, divide it by the molar volume of gas:
Number of moles = Volume of gas / Molar volume
Number of moles = 11.2 L / 22.4 L/mol
Step 3: Calculate the number of moles of oxygen atoms.
In ozone (O3), there are 3 oxygen atoms in 1 molecule:
Number of moles of oxygen atoms = 3 × Number of moles of ozone
Step 4: Convert the number of moles of oxygen atoms to the number of atoms.
To convert moles to atoms, we use Avogadro's number, which is approximately 6.022 × 10^23 atoms/mol:
Number of atoms = Number of moles of oxygen atoms × Avogadro's number
Now, let's calculate the number of atoms of oxygen in 11.2 L of ozone at NTP:
Number of moles = 11.2 L / 22.4 L/mol
Number of moles = 0.5 mol (rounded to one decimal place)
Number of moles of oxygen atoms = 3 × 0.5 mol
Number of moles of oxygen atoms = 1.5 mol
Number of atoms = 1.5 mol × 6.022 × 10^23 atoms/mol
Number of atoms = 9.033 × 10^23 atoms
Therefore, there are approximately 9.033 × 10^23 atoms of oxygen present in 11.2 L of ozone at NTP.