What is the Van't Hoff factor for NaSO3
The Van't Hoff factor for NaSO3 is 2.
This is because NaSO3 dissociates in water to form two particles in solution: one sodium ion (Na+) and one sulfite ion (SO3
2-). Each ion contributes to the total number of particles in solution, so the Van't Hoff factor is equal to the total number of particles formed after dissolution. In this case, there are two particles formed (Na+ and SO3
2-), hence the Van't Hoff factor is 2.
The Van't Hoff factor (i) represents the number of particles that a compound dissociates into in a solution.
To determine the Van't Hoff factor for NaSO3, we need to determine if the compound dissociates into ions when dissolved in water.
NaSO3 (sodium sulfite) consists of a sodium ion (Na+) and a sulfite ion (SO3^2-). When this compound dissolves in water, it dissociates into these ions.
Na2SO3 → 2Na+ + SO3^2-
Therefore, the Van't Hoff factor for NaSO3 is 2, as it dissociates into two ions when dissolved in water.