an unknown substance with mass of 1.2 kg loses 32 kJ of thermal energy. which causes the temperature to drop from 364.0 k to 304.6 k. identify the unknown sustenance
To identify the unknown substance, we can use the formula for specific heat:
Q = mcΔT
Where:
Q is the thermal energy lost or gained
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
Rearranging the formula, we get:
c = Q / (mΔT)
Plugging in the given values, we have:
c = -32 kJ / (1.2 kg * (304.6 K - 364.0 K))
Calculating the denominator first:
ΔT = 304.6 K - 364.0 K
ΔT = -59.4 K
Now, plugging in the values:
c = -32 kJ / (1.2 kg * -59.4 K)
c ≈ 0.449 kJ/(kg·K)
Using specific heat capacity tables or reference books, we can identify substances with a specific heat capacity close to 0.449 kJ/(kg·K).
To identify the unknown substance, we can make use of the specific heat capacity formula:
q = mcΔT
where:
q is the thermal energy change
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
Given:
mass (m) = 1.2 kg
thermal energy change (q) = -32 kJ (negative sign represents energy loss)
temperature change (ΔT) = 364.0 k - 304.6 k = 59.4 k
Now we can rearrange the formula to solve for the specific heat capacity (c):
c = q / (m * ΔT)
Substituting the given values:
c = -32 kJ / (1.2 kg * 59.4 k)
Calculating:
c ≈ -32,000 J / (1.2 kg * 59.4 K)
c ≈ -449.438 J/(kg*K)
Since specific heat capacity is a material-specific property, we would require additional information to determine the unknown substance.