a 100 kg mass is dropped from a height of 3.0 m. the kinetic energy before striking the ground is
To find the kinetic energy before striking the ground, we need to use the equation:
Kinetic Energy = (1/2)mass x velocity^2
First, let's calculate the final velocity of the mass right before impact.
Using the equation:
Potential Energy = mass x gravity x height
Potential Energy = 100 kg x 9.8 m/s^2 x 3.0 m
Potential Energy = 2940 Joules
The potential energy will convert to kinetic energy right before reaching the ground. Therefore, the kinetic energy is equal to the potential energy:
Kinetic Energy = 2940 Joules
So, the kinetic energy before striking the ground is 2940 Joules.
To calculate the kinetic energy of the mass before it strikes the ground, you can use the equation for kinetic energy:
Kinetic Energy = (1/2) * mass * velocity^2
First, let's calculate the final velocity of the mass just before it hits the ground. We can use the principle of conservation of energy, which states that the potential energy lost by the mass as it falls will be equal to the kinetic energy gained.
Potential Energy lost = m * g * h
where:
m = mass of the object (100 kg)
g = acceleration due to gravity (9.8 m/s^2)
h = height (3.0 m)
Potential Energy lost = 100 kg * 9.8 m/s² * 3.0 m
Potential Energy lost = 2940 Joules
Since the potential energy lost is equal to the kinetic energy gained, we can substitute this value into the kinetic energy equation:
Kinetic Energy = 2940 Joules
So, the kinetic energy of the mass just before striking the ground is 2940 Joules.