The probabilities that john and joseph pass an examination is 3/4 and 3/5 respectively. Find the probability that both boys failing the examination
(1 - 3/4) * (1 - 3/5) = 1/10
The probability that both boys fail the examination is 1/10.
To find the probability that both boys fail the examination, we can find the probability of John passing the exam and Joseph passing the exam, and subtract this from 1.
The probability that John passes the exam is given as 3/4, so the probability he fails is 1 - 3/4 = 1/4.
Similarly, the probability that Joseph passes the exam is given as 3/5, so the probability he fails is 1 - 3/5 = 2/5.
Now, we can multiply the probabilities of both boys failing:
Probability of both boys failing = (1/4) * (2/5) = 2/20 = 1/10.
Therefore, the probability that both boys fail the examination is 1/10.
To find the probability that both boys fail the examination, we need to find the probability of John failing the examination, multiplied by the probability of Joseph failing the examination.
Given that the probability John passes the examination is 3/4, the probability he fails is 1 - 3/4 = 1/4.
Given that the probability Joseph passes the examination is 3/5, the probability he fails is 1 - 3/5 = 2/5.
To find the probability that both boys fail, we multiply the probability of John failing (1/4) by the probability of Joseph failing (2/5):
(1/4) * (2/5) = 2/20 = 1/10
Therefore, the probability that both boys fail the examination is 1/10.