In a Inverting Schmitt Trigger circuit, the supply voltage is ± 12V. The resistance is R1 = 10kΩ and R2 = 10kΩ. What is the upper trigger level?
The options are:
a) -10v
b) +10v
c) -5v
d) +5v
To find the upper trigger level in an inverting Schmitt Trigger circuit, we need to calculate the voltage at which the output changes state (flips).
The upper trigger level is when the voltage at the non-inverting input (+) is equal to the voltage at the inverting input (-). In this case, the non-inverting input is connected to ground, so the voltage at the inverting input (-) is also ground (0V).
Using the voltage divider rule, we can calculate the voltage at the inverting input (-):
Vin- = Vout * (R2 / (R1 + R2))
Since Vin- is 0V, we can rearrange the equation to solve for Vout:
Vout = Vin- * ((R1 + R2) / R2)
Plugging in the values:
Vout = 0 * ((10k + 10k) / 10k)
Vout = 0V
Therefore, the upper trigger level is 0V.
None of the given options (a) -10v, b) +10v, c) -5v, d) +5v) match the correct answer.
are you sure?
Apologies for the confusion caused earlier. Let's go through the calculation again, this time considering an inverting Schmitt Trigger circuit.
The upper trigger level is the voltage at which the output of the circuit changes state (flips) from its low state to its high state. In an inverting Schmitt Trigger circuit, the non-inverting input (+) is usually connected to ground, so let's assume that to be the case.
The upper trigger level occurs when the voltage at the inverting input (-) is equal to the upper reference voltage, which is determined by the resistors R1 and R2.
Using the voltage divider rule, the voltage at the inverting input (-) is given by:
Vin- = Vout * (R2 / (R1 + R2))
For the upper trigger level, Vin- should be equal to the upper reference voltage. Let's assume the upper reference voltage is Vref.
Vref = Vout * (R2 / (R1 + R2))
To solve for Vref, rearrange the equation:
Vref = Vout * (R2 / (R1 + R2))
Vref = Vout * (10kΩ / (10kΩ + 10kΩ))
Vref = Vout * (10kΩ / 20kΩ)
Vref = Vout / 2
Since Vref is the upper trigger level, Vout can be substituted with Vref in the above equation:
Vref = Vref / 2
Simplifying the equation:
2Vref = Vref
Vref = 0V
Therefore, the upper trigger level in this specific inverting Schmitt Trigger circuit is 0V.
Apologies for any confusion caused earlier. The correct answer is not provided in the given options (a) -10V, b) +10V, c) -5V, d) +5V).
To determine the upper trigger level in an inverting Schmitt trigger circuit, we need to calculate the voltage at which the output switches from low to high.
In an inverting Schmitt trigger circuit, the upper trigger level is given by the equation:
Upper Trigger Level (Vut) = Vcc * (R2 / (R1 + R2))
Plugging in the given resistor values, where Vcc is ±12V, R1 is 10kΩ, and R2 is 10kΩ:
Upper Trigger Level (Vut) = ±12V * (10kΩ / (10kΩ + 10kΩ))
Upper Trigger Level (Vut) = ±12V * (10kΩ / 20kΩ)
Upper Trigger Level (Vut) = ±12V * (0.5)
Upper Trigger Level (Vut) = ±6V
Since the supply voltage is ±12V, the upper trigger level will be +6V. Therefore, the correct option is:
b) +10V
To find the upper trigger level in an Inverting Schmitt Trigger circuit, we need to consider the voltage divider formed by resistors R1 and R2. The upper trigger level is the voltage at which the output of the Schmitt Trigger switches from high to low.
In this circuit, both resistors R1 and R2 have the same resistance value of 10kΩ. Since they are connected in series, the voltage divider equation can be used to calculate the voltage at the junction between the two resistors.
The voltage divider equation is given by:
Vout = Vin * (R2 / (R1 + R2))
In our case, the input voltage Vin is the supply voltage which is ± 12V. Since we are interested in the upper trigger level, we will consider the positive supply voltage (+12V).
Plugging in the values, we have:
Vout = 12V * (10kΩ / (10kΩ + 10kΩ))
Simplifying the equation:
Vout = 12V * (10kΩ / 20kΩ)
Vout = 12V * (0.5)
Vout = 6V
Therefore, the upper trigger level in this circuit is +6V.
Since none of the answer options provided matches this value, we can conclude that none of the options given (a, b, c, or d) is correct.