A fair coin is tossed two
times in succession. The set of equally likely outcomes is StartSet HH comma HT comma TH comma TT EndSet
.
Find the probability of getting exactly one head
.
The total number of outcomes is 4 (HH, HT, TH, TT).
The event of getting exactly one head can occur in 2 ways (HT, TH).
So, the probability of getting exactly one head is 2/4 = 0.5.
To find the probability of getting exactly one head when a fair coin is tossed two times in succession, we need to determine the number of favorable outcomes (getting exactly one head) and the total number of possible outcomes.
The favorable outcomes are HT and TH, which means there are 2 favorable outcomes.
The total number of possible outcomes is 4, as there are 2 choices (heads or tails) for each coin, and we are tossing the coin twice.
Therefore, the probability of getting exactly one head is:
Number of favorable outcomes / Total number of possible outcomes
= 2 / 4
= 1/2
So, the probability of getting exactly one head is 1/2.