If we cross 2 pea plants that are heterozygous green (Gg). Green is dominant and yellow recessive. What would the genotype and phenotype result? Create your Punnett square and make the cross. List the genotype (include number of each) and phenotype (number of each)
The Punnett square for crossing two heterozygous green pea plants (Gg) is as follows:
G g
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G | GG | Gg |
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g | Gg | gg |
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The genotype and phenotype results would be:
- Genotype:
- GG: 1 individual
- Gg: 2 individuals
- gg: 1 individual
- Phenotype:
- Green (dominant): 3 individuals
- Yellow (recessive): 1 individual
To create a Punnett square and determine the genotype and phenotype ratio for the cross between two heterozygous green pea plants (Gg), we can follow these steps:
1. Set up the Punnett square by writing the alleles for each parent plant along the top and left side of the square. In this case, both parent plants are heterozygous green, so we have Gg x Gg.
G g
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G | | |
g | | |
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2. Fill in the boxes of the Punnett square by combining the alleles from each parent. Each parent contributes one allele to each offspring. In this case, we would fill in the boxes as follows:
G g
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G | GG | Gg |
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g | Gg | gg |
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3. Determine the genotype and phenotype ratio by counting the number of each genotype and phenotype in the Punnett square:
- Genotype:
- GG: 1
- Gg: 2
- gg: 1
- Phenotype (based on the dominance of green):
- Green (GG and Gg): 3
- Yellow (gg): 1
Therefore, the genotype ratio is 1 GG : 2 Gg : 1 gg, and the phenotype ratio is 3 Green : 1 Yellow.