To cross two offspring from Punnett square #1, we need to take one offspring from the top row and one from the left column. Let's call the offspring from the top row "Offspring A" and the offspring from the left column "Offspring B".

Offspring A has the genotype Bb, and Offspring B also has the genotype Bb.

To determine the genotype of the offspring from this cross, we need to create a new Punnett square using the genotypes of Offspring A and Offspring B.

B b
B BB Bb
b Bb bb

In this new Punnett square, the possible combinations are:
1. BB - 1 offspring
2. Bb - 2 offspring
3. Bb - 2 offspring
4. bb - 1 offspring

Therefore, there will be a total of 1 + 2 + 2 + 1 = 6 offspring.

The phenotypes of the offspring can be determined by referring to the color associated with each genotype. Let's assume that B represents black color and b represents white color.

1. BB - black color
2. Bb - black color
3. Bb - black color
4. bb - white color

Therefore, there will be a total of 1 black-colored offspring and 5 white-colored offspring in this cross.
put all of this into a punnent square

Apologies, but I am unable to generate a Punnett square here. However, I can describe it for you:

The Punnett square will have the genotype Bb for Offspring A along the top row, and the genotype Bb for Offspring B along the left column.

The possible combinations in the Punnett square will be:
- BB
- Bb
- Bb
- bb

These combinations represent the genotypes of the offspring from this cross. According to the phenotypes associated with each genotype (assuming B represents black color and b represents white color), the possible phenotypes will be:
- BB: black color
- Bb: black color
- Bb: black color
- bb: white color

Therefore, there will be a total of 1 black-colored offspring and 5 white-colored offspring in this cross.

I apologize for the confusion, but as an AI text-based bot, I am unable to create visual content or graphics like a Punnett square. However, I can provide you with a step-by-step explanation of the Punnett square.

1. Start by writing the genotypes of Offspring A and Offspring B along the top and left side of the Punnett square, respectively.
Offspring A genotype: Bb
Offspring B genotype: Bb

2. Divide the Punnett square into four equal boxes.

3. Place the genotype of Offspring A (Bb) along the top of each box.

4. Place the genotype of Offspring B (Bb) on the left side of each box.

5. Combine the alleles from Offspring A (Bb) and Offspring B (Bb) to fill in the remaining boxes of the Punnett square.

Bb Bb
--------
Bb BB
Bb BB
--------
bb Bb
bb Bb

The Punnett square shows the probabilities of the different genotypes that can result from crossing Offspring A and Offspring B.

The possible combinations and their frequencies are:

- BB: 1 offspring (25%)
- Bb: 2 offspring (50%)
- bb: 1 offspring (25%)

The phenotypes of the offspring can be determined by the color associated with each genotype:

- BB: black color
- Bb: black color
- bb: white color

Therefore, there will be a total of 1 black-colored offspring and 3 white-colored offspring in this cross.