Punnett square #1
B b
B BB Bb
b Bb bb
cross two offspring from Punnett square #1
The genotype of offspring (give a number of each genotype) Phenotype of offspring (give the color of the phenotype(s))
To cross two offspring from Punnett square #1, we need to take one offspring from the top row and one from the left column. Let's call the offspring from the top row "Offspring A" and the offspring from the left column "Offspring B".
Offspring A has the genotype Bb, and Offspring B also has the genotype Bb.
To determine the genotype of the offspring from this cross, we need to create a new Punnett square using the genotypes of Offspring A and Offspring B.
B b
B BB Bb
b Bb bb
In this new Punnett square, the possible combinations are:
1. BB - 1 offspring
2. Bb - 2 offspring
3. Bb - 2 offspring
4. bb - 1 offspring
Therefore, there will be a total of 1 + 2 + 2 + 1 = 6 offspring.
The phenotypes of the offspring can be determined by referring to the color associated with each genotype. Let's assume that B represents black color and b represents white color.
1. BB - black color
2. Bb - black color
3. Bb - black color
4. bb - white color
Therefore, there will be a total of 1 black-colored offspring and 5 white-colored offspring in this cross.
To cross two offspring from Punnett square #1, we can take one offspring with genotype BB and another offspring with genotype Bb.
When we cross these two, we can set up a new Punnett square to determine the genotypes and phenotypes of the offspring.
B b
B BB Bb
b Bb bb
Crossing BB with Bb:
B B
B BB BB
b Bb Bb
The genotypes of the offspring are:
- 2 offspring with genotype BB
- 2 offspring with genotype Bb
The phenotype refers to the physical appearance, in this case the color of the offspring. Let's assume that B represents a dominant allele for black color and b represents a recessive allele for brown color. In this case, the phenotype of the offspring would be:
- 4 offspring with the black color phenotype