BeCl2 is obey octate rule?
No, BeCl2 does not obey the octet rule. The octet rule states that most atoms tend to gain, lose, or share electrons in order to have a full outer shell of eight electrons (or two electrons for hydrogen). However, beryllium only has four valence electrons and can only form two bonds. In BeCl2, beryllium forms two covalent bonds with two chlorine atoms, resulting in a linear molecule with only four valence electrons around beryllium.
No, BeCl2 does not obey the octet rule. The octet rule states that atoms tend to gain, lose, or share electrons in order to have a complete outer shell with eight electrons (except for hydrogen, which only requires two electrons).
Beryllium (Be) has two valence electrons, so according to the octet rule, it would need to gain six more electrons to achieve a full octet. However, BeCl2 consists of one beryllium atom bonded to two chlorine atoms. In this molecule, beryllium only has four electrons around it (two from each chlorine atom), which is not a full octet.
BeCl2 is an example of a compound that violates the octet rule. It is known as a Lewis acid because the beryllium atom can accept a pair of electrons to complete its octet.