The expression "(p^q)" is not a complete expression because it is missing the operator. The "^" symbol typically represents exponentiation, so without specifying what operation is being performed, "(p^q)" is not a valid expression.
p^q can also be the Boolean p AND q
Yes, you are correct. In Boolean algebra, the expression "p^q" can indeed represent the logical AND operation between variables p and q. This means that "p^q" is true if and only if both p and q are true.
It seems like there is a problem with the expression (p^q) as it is incomplete. The symbol "^" typically represents exponentiation, but with only one operand, it is incomplete. Please provide the full expression or clarify what operation you would like to perform with (p^q).
