A car of mass 1000kg is driven from its initial state with uniform acceleration and reaches a speed of 30km/h in 10sec. Find the force exerted by the engine
To find the force exerted by the engine, we can use Newton's second law of motion:
Force = Mass x Acceleration
Given:
Mass of the car (m) = 1000 kg
Time taken (t) = 10 sec
Final velocity (v) = 30 km/h = 8.33 m/s (converted from km/h to m/s)
Acceleration (a) can be calculated using the formula:
a = (v - u) / t
where u is the initial velocity, which is 0 m/s (since the car starts from rest).
Plugging in the given values:
a = (8.33 m/s - 0 m/s) / 10 sec
a = 0.833 m/s²
Now, we can calculate the force:
Force = Mass x Acceleration
Force = 1000 kg x 0.833 m/s²
Force = 833 Newtons
Therefore, the force exerted by the engine is 833 Newtons.
To find the force exerted by the engine, we can use Newton's second law of motion:
Force = mass × acceleration
Given:
Mass of the car, m = 1000 kg
Initial velocity, u = 0 (since the initial state is at rest)
Final velocity, v = 30 km/h = (30 × 1000) / 3600 = 8.33 m/s
Time taken, t = 10 sec
We can calculate the acceleration using the formula:
Acceleration = (Final velocity - Initial velocity) / Time taken
Acceleration = (8.33 m/s - 0 m/s) / 10 sec = 0.833 m/s^2
Now, we can substitute the values in the formula for force:
Force = mass × acceleration
Force = 1000 kg × 0.833 m/s^2
Force = 833 N
Therefore, the force exerted by the engine is 833 Newtons.