What must be subtracted from the sum of 2 1/6 and 2 7/12 to give 3 1/4
To find the value that must be subtracted, first convert all the mixed numbers to improper fractions:
2 1/6 = (2 * 6 + 1)/6 = 13/6
2 7/12 = (2 * 12 + 7)/12 = 31/12
3 1/4 = (3 * 4 + 1)/4 = 13/4
Now, find the sum of 13/6 and 31/12:
13/6 + 31/12 = (13 * 2 + 31)/12 = 57/12 = 19/4
To find the value that must be subtracted from 19/4 to give 13/4, subtract 13/4 from 19/4:
19/4 - 13/4 = 6/4 = 3/2
Therefore, the value that must be subtracted is 3/2.
To find out what must be subtracted from the sum of 2 1/6 and 2 7/12 to give 3 1/4, we need to calculate the sum first and then subtract it from 3 1/4.
Step 1: Convert the fractions to have a common denominator.
2 1/6 = 13/6
2 7/12 = 31/12
Step 2: Find the sum of 13/6 and 31/12.
13/6 + 31/12 = (2*13 + 31)/12 = (26 + 31)/12 = 57/12
Step 3: Convert 3 1/4 to have a denominator of 12.
3 1/4 = 13/4
Step 4: Subtract the sum from 3 1/4.
13/4 - 57/12 = (3*13 - 57)/12 = (39 - 57)/12 = -18/12
Step 5: Simplify the fraction.
-18/12 can be simplified to -3/2.
Therefore, you must subtract 3/2 (or 1 1/2) from the sum of 2 1/6 and 2 7/12 to give 3 1/4.