An irregular polygon has its external angles 140°,120°,142°,132°,112°,and x°.find the value of x .
To find the value of x, we can use the fact that the sum of the external angles of any polygon is always 360 degrees.
Given that the external angles of the irregular polygon are 140°, 120°, 142°, 132°, 112°, and x°, we can write the equation:
140° + 120° + 142° + 132° + 112° + x° = 360°
Now, let's solve for x:
646° + x° = 360°
Subtract 646° from both sides of the equation:
x° = 360° - 646°
x° = -286°
Therefore, the value of x is -286°.
To find the value of x, we need to use the property that the sum of the external angles of any polygon is 360 degrees.
The sum of the given external angles is 140° + 120° + 142° + 132° + 112° + x° = 646°.
To find x, we subtract the sum of the known angles from 360°: 360° - 646° = -286°.
Therefore, the value of x is -286°.