Two dice are thrown at the same time ..what is the the probability that the sum will be 7 or 11
To find the probability that the sum will be 7 or 11 when two dice are thrown at the same time, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes.
Possible outcomes when two dice are thrown: 6 * 6 = 36 (as each die has 6 possible outcomes: 1, 2, 3, 4, 5, 6)
Now let's determine the favorable outcomes:
For the sum to be 7, the possible combinations are:
(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) -> total of 6 combinations
For the sum to be 11, the only combination is:
(5, 6) -> 1 combination
Total number of favorable outcomes = 6 + 1 = 7
Therefore, the probability that the sum will be 7 or 11 is 7/36 or approximately 0.1944 or 19.44%.
To find the probability of getting a sum of 7 or 11 when two dice are thrown, we need to determine the total number of possible outcomes and the number of favorable outcomes.
There are 6 possible outcomes for each die, as each die has 6 faces numbered from 1 to 6. Thus, the total number of possible outcomes is 6 * 6 = 36.
Now let's consider the favorable outcomes:
To get a sum of 7:
The possible combinations are (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1). There are 6 possible combinations that result in a sum of 7.
To get a sum of 11:
The possible combinations are (5, 6) and (6, 5), as these are the only combinations that sum up to 11.
Therefore, the number of favorable outcomes is 6 + 2 = 8.
Now we can find the probability:
Probability = (Number of favorable outcomes) / (Number of possible outcomes)
= 8 / 36
= 2 / 9
So, the probability of getting a sum of 7 or 11 when two dice are thrown is 2/9.