A solid of mass 1.7kg suspended by a string is completely in water if the tension in the spring is 6N calculate
1. Upthrust of the solid
2.volume of the solid
3. Density of the solid
4. Relative density of the solid
1. The upthrust of the solid is equal to the weight of the water displaced by the solid. This is given by Archimedes' principle, which states that the upthrust is equal to the weight of the fluid displaced by the object.
The weight of the solid is given by mass x gravitational acceleration, which is approximately 9.8 m/s^2. Thus, the weight of the solid is 1.7 kg x 9.8 m/s^2 = 16.66 N.
Since the tension in the string is 6 N, the upthrust must also be 6 N to achieve equilibrium. Therefore, the upthrust of the solid is 6 N.
2. The volume of the solid can be calculated using the equation for upthrust:
Upthrust = weight of water displaced by the solid
The density of water is 1000 kg/m^3.
density of water x volume of solid x gravitational acceleration = weight of water displaced by the solid
1000 kg/m^3 x volume of solid x 9.8 m/s^2 = 6 N
Volume of solid = 6 N / (1000 kg/m^3 x 9.8 m/s^2) = 0.0006122 m^3
3. The density of the solid can be calculated using the equation for density:
Density = mass / volume
Density = 1.7 kg / 0.0006122 m^3 = 2781 kg/m^3
4. The relative density of the solid can be calculated by comparing the density of the solid to the density of water:
Relative Density = Density of solid / Density of water
Relative Density = 2781 kg/m^3 / 1000 kg/m^3 = 2.781
To calculate the upthrust of the solid, we can use Archimedes' principle, which states that the upthrust on a submerged object is equal to the weight of the fluid it displaces.
1. Upthrust of the solid:
The upthrust is equal to the weight of the water displaced by the solid. Since the solid is completely submerged, the upthrust is equal to the weight of the solid. In this case, the tension in the string is balancing the weight of the solid, so the upthrust is also 6N.
2. Volume of the solid:
The volume of the solid can be found using the formula:
Density = Mass / Volume
First, let's find the volume of the solid. We know the mass of the solid is 1.7kg. We also know that the density of water is approximately 1000 kg/m^3.
Since the solid is completely submerged, it displaces an equal volume of water. Therefore, the volume of the solid is the same as the volume of water displaced.
Volume = Mass of solid / Density of water
Volume = 1.7kg / 1000 kg/m^3
Volume = 0.0017 m^3
3. Density of the solid:
Using the formula Density = Mass / Volume, we can calculate the density of the solid. We know the mass of the solid is 1.7kg, and the volume of the solid is 0.0017 m^3.
Density = Mass / Volume
Density = 1.7kg / 0.0017 m^3
Density = 1000 kg/m^3
Therefore, the density of the solid is 1000 kg/m^3.
4. Relative density of the solid:
The relative density of the solid is the ratio of its density to the density of water.
Relative density = Density of the solid / Density of water
Relative density = 1000 kg/m^3 / 1000 kg/m^3
Relative density = 1
Therefore, the relative density of the solid is 1.