Although playing chess doesn't intrigue
Connor, he agreed to play a few games with Peter. Peter has a real knack for the game and easily defeated Connor every time they played. The first game lasted half of an hour. The second game took one-fifth of an hour and the third game was over in one and two-thirds hours. How long did it take Peter to defeat Connor all three times?
To find the total time for all three games, we need to add up the individual game times. The first game lasted half hour, which can be represented as 1/2 hour. The second game lasted 1/5 hour, and the third game lasted 1 2/3 hours, which can be converted to 1 + 2/3 = 3/3 + 2/3 = 5/3 hours.
Adding up the game times, we get 1/2 + 1/5 + 5/3 = (15 + 6 + 25)/30 = 46/30
The fraction can be simplified further by dividing the numerator and denominator by their greatest common divisor, which is 2.
Thus, 46/30 can be simplified to 23/15.
Therefore, Peter took 23/15 hours to defeat Connor in all three games.
To find out how long it took Peter to defeat Connor all three times, we need to add up the durations of each game.
The first game lasted half an hour, which is equivalent to 0.5 hours.
The second game took one-fifth of an hour, which is equivalent to 0.2 hours.
The third game was over in one and two-thirds hours, which is equivalent to 1.67 hours.
To find the total duration, we sum up the durations of each game: 0.5 + 0.2 + 1.67 = 2.37 hours.
Therefore, it took Peter 2.37 hours to defeat Connor all three times.