A glass cup of juice is found to have poH of 11.40.Calculate the concentration of the hydroxide ions in the juice
First, we need to find the pOH of the juice by subtracting the pH from 14 (since pH + pOH = 14):
pOH = 14 - 11.40 = 2.6
Next, we can use the relationship between pOH and [OH-]:
pOH = -log[OH-]
2.6 = -log[OH-]
Taking the antilog of both sides:
[OH-] = 10^-2.6 = 0.00251 M
Therefore, the concentration of hydroxide ions in the juice is 0.00251 M.
To calculate the concentration of hydroxide (OH-) ions in the juice, we can use the formula for pH:
pOH = -log[OH-]
Given that the pOH of the juice is 11.40, we can calculate the concentration of hydroxide ions (OH-) as follows:
pOH = -log[OH-]
11.40 = -log[OH-]
Now, let's solve for [OH-] by rearranging the equation:
[OH-] = 10^(-pOH)
Substituting the value of pOH into the equation, we get:
[OH-] = 10^(-11.40)
Evaluating the expression, we find:
[OH-] ≈ 3.981 x 10^(-12) M
Therefore, the concentration of hydroxide ions in the juice is approximately 3.981 x 10^(-12) M.