A spiral is compressed by0.3mcalculate the energy stored in the spring if it force is constant is 300meter per second
Squared.
We can use the formula for the potential energy stored in a spring:
PE = (1/2)kx^2
Where k is the spring constant and x is the displacement or compression of the spring.
First, we need to calculate the new compression of the spring after it has been compressed by 0.3m:
x = 0.3m
Next, we need to determine the spring constant. We are given the force, so we can use the equation:
F = kx
Rearranging, we get:
k = F/x
Substituting the values, we get:
k = 300 N/m / 0.3 m
k = 1000 N/m
Now, we can plug in the values to calculate the potential energy stored in the spring:
PE = (1/2)kx^2
PE = (1/2)(1000 N/m)(0.3m)^2
PE = 45 J
Therefore, the energy stored in the spring is 45 Joules.
To calculate the energy stored in a compressed spring, we can use the formula for potential energy in a spring:
Potential energy (PE) = 0.5 * k * x^2
Where:
PE is the potential energy stored in the spring,
k is the spring constant, and
x is the displacement/compression of the spring.
In this case, we are given:
Compression (x) = 0.3 m
Force (F) = 300 N
Spring constant (k) = F/x
Let's substitute the given values into the formula:
k = F/x = 300 N / 0.3 m = 1000 N/m
Now, we can calculate the potential energy:
PE = 0.5 * k * x^2
PE = 0.5 * 1000 N/m * (0.3 m)^2
PE = 0.5 * 1000 N/m * 0.09 m^2
PE = 45 joules
Therefore, the energy stored in the spring is 45 joules.