how to develop an algorithm read 10 integer from the key board in the range 0 up to 100 and count how many them are larger than 50 and display this result
1. Set the counter for integers over 50 to zero.
2. Create a loop to read 10 integers from the keyboard.
3. For each integer read from the keyboard, check if it's in the range of 0 to 100.
4. If the integer is not in the range of 0 to 100, display an error message and ask for another integer.
5. If the integer is in the range of 0 to 100, check if it's larger than 50.
6. If the integer is larger than 50, increment the counter for integers over 50.
7. After reading all 10 integers, display the count of integers that are larger than 50.
Pseudo Code:
counter = 0
for i in range(10):
read integer from keyboard
if integer < 0 or integer > 100:
display error message
i -= 1 # to repeat this iteration
else:
if integer > 50:
counter += 1
display counter
To develop an algorithm that reads 10 integers from the keyboard in the range of 0 up to 100, and counts how many of them are larger than 50, follow these steps:
1. Initialize a variable called "count" to 0. This variable will keep track of the count of integers greater than 50.
2. Create a loop that iterates 10 times to read 10 integers from the keyboard.
2.1. Inside the loop, prompt the user to input an integer and read the value from the keyboard.
2.2. Check if the entered value is greater than 50.
2.2.1. If the value is greater than 50, increment the "count" variable by 1.
3. After the loop ends, display the value of the "count" variable, which represents the number of integers greater than 50.
Here is a sample algorithm in pseudo-code:
```
count = 0
for i = 1 to 10:
inputNumber = readInputFromKeyboard()
if inputNumber > 50:
count = count + 1
display count
```
You can implement this algorithm in your preferred programming language.