Which is more concentrated vinegar ( 5%. {W/V }acetic acid) or 1 M acetic acid.

1 M acetic acid is more concentrated than vinegar (5% W/V acetic acid).

can u solve it

Yes, I can explain it.

The concentration of vinegar is given in terms of mass/volume percentage i.e., 5% (W/V) acetic acid means 5 grams of acetic acid in 100 ml of vinegar. On the other hand, 1 M acetic acid means 1 mole of acetic acid in 1 liter of solution.

To compare the concentration of both solutions, we need to convert them to the same unit. We can convert 5% (W/V) acetic acid to molarity using the formula:

Molarity = (Mass of solute in grams / Molar mass of solute) / Volume of solution in liters

The molar mass of acetic acid is 60.05 g/mol. Therefore, the molarity of 5% (W/V) acetic acid solution can be calculated as:

Molarity = (5 g / 60.05 g/mol) / (100 ml / 1000 ml/L) = 0.83 M

This means that 1 M acetic acid solution is more concentrated than 5% (W/V) acetic acid solution.

To determine which is more concentrated, we need to compare the percentages and molar concentrations of the two solutions: 5% W/V acetic acid and 1 M acetic acid.

1. 5% W/V acetic acid: This means that in 100 mL of solution, there are 5 grams of acetic acid (CH3COOH). The rest of the solution is water.

2. 1 M acetic acid: A 1 M solution means that there is 1 mole of acetic acid dissolved in 1 liter (1000 mL) of solution.

To compare the concentrations, we need to convert the percentage concentration to molar concentration:

1. Calculate the molar mass of acetic acid (CH3COOH):
C = 12.01 g/mol
H = 1.01 g/mol
O = 16.00 g/mol
2(H) + 4(C) + 2(O) = 2(1.01) + 4(12.01) + 2(16.00) = 60.05 g/mol

2. Convert percentage concentration to grams:
5% of 100 mL = 5 grams (since the density of water is approximately 1 g/mL)

3. Convert grams to moles:
Moles = grams / molar mass
Moles of acetic acid = 5 g / 60.05 g/mol = 0.0832 moles

4. Now, let's compare the molar concentration of 1 M acetic acid:
1 M acetic acid = 1 mole / 1 liter = 1 mole / 1000 mL
1 M acetic acid = 0.0832 moles

Comparing the two concentrations, we see that both the 5% W/V acetic acid and 1 M acetic acid solutions have the same molar concentration of 0.0832 moles. Therefore, they have the same concentration, despite being expressed differently.