A common solution used by EMTs for keeping VEINS from collapsing in accident victims is 5% (m/v) dextrose (C6H12O6) in water. calculate the molarity of 5 %(m/v) dextrose in water .
To calculate the molarity of 5% (m/v) dextrose in water, we need to first convert the percentage to grams per liter:
5% (m/v) = 5 grams per 100 mL
We need to convert 100 mL to liters:
100 mL = 0.1 L
So, the concentration of dextrose in water is 5 grams per 0.1 liter, or 50 grams per liter.
Next, we need to calculate the molecular weight of dextrose (C6H12O6):
C = 12.01 g/mol
H = 1.01 g/mol
O = 16.00 g/mol
The molecular weight of dextrose is:
(6 x 12.01) + (12 x 1.01) + (6 x 16.00) = 180.18 g/mol
Finally, we can calculate the molarity of dextrose in water:
Molarity = moles of solute / liters of solution
To find the moles of dextrose in 1 liter of solution, we divide the mass by the molecular weight:
50 g / 180.18 g/mol = 0.277 moles
So, the molarity of 5% (m/v) dextrose in water is:
0.277 moles / 1 liter = 0.277 M
To calculate the molarity of a 5% (m/v) dextrose solution in water, we first need to convert the given percentage to grams of dextrose.
Step 1: Convert percentage to grams
Since a 5% (m/v) solution means 5 grams of dextrose per 100 mL of solution, we need to find the number of grams in 1 liter (1000 mL) of solution.
5 grams / 100 mL = x grams / 1000 mL
Cross-multiply:
1000x = 5 * 100
1000x = 500
Divide by 1000:
x = 500/1000
x = 0.5 grams
So, there are 0.5 grams of dextrose in 1 liter of solution.
Step 2: Calculate molarity
The molarity (M) is defined as the number of moles of solute per liter of solution. To find the molarity, we need to know the molar mass of dextrose.
The molecular formula of dextrose (glucose) is C6H12O6.
To calculate the molar mass, we sum up the atomic masses of each element:
Molar mass of C6H12O6 = (6*12.01) + (12*1.01) + (6*16.00)
= 72.06 + 12.12 + 96.00
= 180.18 g/mol
Now, we can calculate the molarity using the equation:
Molarity (M) = moles of solute / volume of solution (in liters)
Since we have 0.5 grams of dextrose in 1 liter of solution, we need to convert the grams to moles before calculating the molarity.
Moles of dextrose = grams of dextrose / molar mass of dextrose
= 0.5 g / 180.18 g/mol
Molarity (M) = (0.5 g / 180.18 g/mol) / 1 L
= (0.5 / 180.18) mol/L
Calculating this division, we find:
Molarity (M) ≈ 0.00277 mol/L
Therefore, the molarity of a 5% (m/v) dextrose in water solution is approximately 0.00277 mol/L.