mole fraction of HNO3 is 0.175. calculate mass of nitric acid and H2O.
Without knowing the total mass of the solution, we can only calculate the relative masses of HNO3 and H2O.
Let's assume there are 1000 g of the solution. Then, the mole fraction of HNO3 is:
Mole fraction of HNO3 = moles of HNO3 / total moles
0.175 = moles of HNO3 / (moles of HNO3 + moles of H2O)
We can rearrange this equation to solve for moles of H2O:
moles of H2O = moles of HNO3 / 0.175 - moles of HNO3
moles of H2O = moles of HNO3 / 0.825
Now, we need to know the molar mass of HNO3 and H2O. HNO3 has a molar mass of 63 g/mol and H2O has a molar mass of 18 g/mol.
The total moles of the solution is:
moles of solution = 1000 g / (63 g/mol x 0.175 + 18 g/mol x moles of H2O)
We can solve for moles of H2O using the equation we derived above and substitute it into the equation for moles of solution:
moles of solution = 1000 g / (63 g/mol x 0.175 + 18 g/mol x (moles of HNO3 / 0.825))
moles of solution = 12.085
Now, we can calculate the mass of HNO3 and H2O:
mass of HNO3 = moles of HNO3 x molar mass of HNO3
mass of HNO3 = 0.175 x 12.085 x 63 g/mol
mass of HNO3 = 133.8 g
mass of H2O = moles of H2O x molar mass of H2O
mass of H2O = (moles of HNO3 / 0.825) x 18 g/mol
mass of H2O = 862.7 g
Therefore, in a 1000 g solution with a mole fraction of HNO3 of 0.175, there are approximately 133.8 g of HNO3 and 862.7 g of H2O.
To calculate the mass of nitric acid (HNO3) and water (H2O), we need to know the total mass or volume of the mixture that contains the HNO3 mole fraction of 0.175.
Let's assume we have a total mass of 100 grams of the mixture. The mole fraction of HNO3 is 0.175, which means that 0.175 moles of HNO3 are present in every 1 mole of the mixture.
To calculate the mass of HNO3, we have to determine the molar mass of HNO3, which is approximately 63 grams/mole.
Mass of HNO3 = Number of moles of HNO3 × Molar mass of HNO3
Mass of HNO3 = 0.175 × 63 grams
Mass of HNO3 = 11.025 grams
To calculate the mass of water (H2O), we need to subtract the mass of HNO3 from the total mass of the mixture.
Mass of H2O = Total mass of the mixture - Mass of HNO3
Mass of H2O = 100 grams - 11.025 grams
Mass of H2O = 88.975 grams
So, the mass of nitric acid (HNO3) is 11.025 grams, and the mass of water (H2O) is 88.975 grams.