calculate W/W, V/V, W/V, mole fraction of solute and solvent and also calculate molarity, molality.weight of C6H6 (benzene)19.5gm, weight of C6H6O (acetone) 15gm.(density of bezene=1.2g/mol, density of acetone 1.5g/mol)
To calculate the quantities requested, we need to know the total volume of the solution. Let's assume that we have mixed 50mL of benzene (density=1.2 g/mL) with 50mL of acetone (density=0.789 g/mL).
To calculate W/W:
- Weight of solute (C6H6O) = 15g
- Weight of solvent (C6H6) = 19.5g
- Total weight of solution = 15g + 19.5g = 34.5g
- W/W of solute = (15g / 34.5g) x 100% = 43.48%
- W/W of solvent = (19.5g / 34.5g) x 100% = 56.52%
To calculate V/V:
- Volume of solute (acetone) = 50mL
- Volume of solvent (benzene) = 50mL
- Total volume of solution = 50mL + 50mL = 100mL
- V/V of solute = (50mL / 100mL) x 100% = 50%
- V/V of solvent = (50mL / 100mL) x 100% = 50%
To calculate W/V:
- Weight of solute (C6H6O) = 15g
- Volume of solvent (benzene) = 50mL
- W/V of solute = (15g / 50mL) x 100% = 30%
- Weight of solvent (C6H6) = 19.5g
- Volume of solvent (benzene) = 50mL
- W/V of solvent = (19.5g / 50mL) x 100% = 39%
To calculate mole fraction:
- Moles of solute (C6H6O) = 15g / 58.08 g/mol = 0.258 moles
- Moles of solvent (C6H6) = 19.5g / 78.11 g/mol = 0.25 moles
- Total moles of solution = 0.258 moles + 0.25 moles = 0.508 moles
- Mole fraction of solute = 0.258 moles / 0.508 moles = 0.508
- Mole fraction of solvent = 0.25 moles / 0.508 moles = 0.492
To calculate molarity:
- Volume of solution = 100mL = 0.1L
- Moles of solute (C6H6O) = 0.258 moles
- Molarity of solute = 0.258 moles / 0.1 L = 2.58 M
To calculate molality:
- Weight of solvent (C6H6) = 19.5g
- Volume of solvent (benzene) = 50mL = 0.05 L
- Moles of solvent (C6H6) = 19.5g / 78.11 g/mol = 0.25 moles
- Molality of solution = 0.258 moles / 0.05 kg = 5.16 mol/kg
To calculate weight of C6H6 (benzene) and C6H6O (acetone):
- Weight of C6H6 (benzene) = 50mL x 1.2 g/mL = 60 g
- Weight of C6H6O (acetone) = 15g
To calculate the values requested, we will use the given information and formulas for the mole fraction, molarity, molality, and weight.
1. Calculate W/W:
W/W is the weight fraction, which represents the ratio of the weight of the solute to the total weight of the solution. In this case, we have benzene (C6H6) and acetone (C6H6O) as solutes.
Weight of benzene = 19.5 g
Weight of acetone = 15 g
Total weight of the solution = Weight of benzene + Weight of acetone
Total weight = 19.5 g + 15 g = 34.5 g
W/W of benzene = (Weight of benzene / Total weight) * 100
W/W of benzene = (19.5 g / 34.5 g) * 100 = 56.5%
W/W of acetone = (Weight of acetone / Total weight) * 100
W/W of acetone = (15 g / 34.5 g) * 100 = 43.5%
2. Calculate V/V:
V/V is the volume fraction, which represents the ratio of the volume of the solute to the total volume of the solution. However, we do not have the volumes of benzene and acetone, so we cannot calculate V/V with the given information.
3. Calculate W/V:
W/V is the weight-to-volume ratio, which represents the weight of the solute divided by the volume of the solution. Since we don't have the volumes, we cannot calculate W/V with the given information.
4. Calculate mole fraction of solute and solvent:
Mole fraction is the ratio of the moles of solute or solvent to the total moles in the solution.
Moles of benzene = Weight of benzene / Molar mass of benzene
Molar mass of benzene = 1.2 g/mol (given)
Moles of benzene = 19.5 g / 1.2 g/mol = 16.25 mol
Moles of acetone = Weight of acetone / Molar mass of acetone
Molar mass of acetone = 1.5 g/mol (given)
Moles of acetone = 15 g / 1.5 g/mol = 10 mol
Total moles = Moles of benzene + Moles of acetone = 16.25 mol + 10 mol = 26.25 mol
Mole fraction of benzene = Moles of benzene / Total moles
Mole fraction of benzene = 16.25 mol / 26.25 mol ≈ 0.620
Mole fraction of acetone = Moles of acetone / Total moles
Mole fraction of acetone = 10 mol / 26.25 mol ≈ 0.380
5. Calculate molarity:
Molarity (M) is the number of moles of solute per liter of solution.
Molarity of benzene = Moles of benzene / Volume of solution (in liters)
Since we don't have the volume of the solution, we cannot calculate molarity with the given information.
6. Calculate molality:
Molality (m) is the number of moles of solute per kilogram of solvent.
Molality of benzene = Moles of benzene / Mass of solvent (in kg)
Since we don't have the mass of benzene (solute), we cannot calculate molality with the given information.
7. Calculate weight of benzene (C6H6):
Weight of benzene = 19.5 g (given)
Therefore, the weight of benzene is already provided as 19.5 g.
I hope this information helps! Let me know if you have any further questions.