Chris's Uncle has a model car. The model is six inches long and three inches wide the actual car is seventy five inches Long what is the car's actual width? If. We assume? The model's proportions are accurate if necessary rang to the nearest tints of an inch
We can use proportions to solve this problem. If we let x be the actual width of the car, then we have:
6/3 = 75/x
Simplifying this, we get:
2 = 75/x
Multiplying both sides by x, we get:
2x = 75
Dividing both sides by 2, we get:
x = 37.5
Therefore, the actual width of the car is 37.5 inches, rounded to the nearest tenth.
To find the car's actual width, we can use the ratio of the model's length to its width and apply it to the actual car's length.
Given:
Model length = 6 inches
Model width = 3 inches
Actual car length = 75 inches
Step 1: Calculate the ratio of the model's length to its width:
Model length : Model width
6 inches : 3 inches
Step 2: Determine the ratio of the model's length to the actual car's length:
Model length : Actual car length
6 inches : 75 inches
Step 3: Calculate the ratio of the model's width to the actual car's width:
Model width : Actual car width
Using the same ratio as the length, we have:
3 inches : Actual car width
Step 4: Set up a proportion to find the actual car's width:
3 inches/6 inches = Actual car width/75 inches
Step 5: Solve for Actual car width:
Cross-multiplying gives us:
(3 inches * 75 inches) / 6 inches = Actual car width
Calculating this gives us:
(225 inches^2) / 6 inches = Actual car width
37.5 inches = Actual car width
Therefore, the car's actual width is approximately 37.5 inches.