Sea water contains 53 PPM of Na2CO3 find mass of and a Na2 CO3. present in a glass of water.
We first need to know the volume of the glass of water in order to find the mass of Na2CO3 present. Let's assume a typical glass of water has a volume of 250 mL (or 0.25 L).
To find the mass of Na2CO3 present, we need to use the given concentration (53 PPM) and convert it to a mass/volume concentration:
53 PPM = 53 mg/L
Now we can use this concentration to find the mass of Na2CO3 in the glass of water:
mass = concentration x volume
mass = 53 mg/L x 0.25 L
mass = 13.25 mg
Therefore, there are 13.25 mg of Na2CO3 present in a typical glass of water.
To find the mass of Na2CO3 present in a glass of water, we can use the given concentration of Na2CO3 in sea water.
1. First, we need to determine the volume of water in the glass. Let's assume the glass contains 250 mL of water.
2. Next, we need to convert the concentration from parts per million (PPM) to grams per liter.
PPM means that there are 53 grams of Na2CO3 in 1 million grams of water.
So, to convert to grams per liter, we divide the PPM value by 1000:
53 PPM / 1000 = 0.053 g/L
3. Now, we can calculate the mass of Na2CO3 in the glass of water.
Since the glass contains 250 mL of water, which is equivalent to 0.25 L, we can use the concentration to calculate the mass:
Mass of Na2CO3 = Concentration x Volume of water
Mass of Na2CO3 = 0.053 g/L x 0.25 L
Mass of Na2CO3 = 0.01325 g
Therefore, there is approximately 0.01325 grams of Na2CO3 present in a glass of water.