Express
4 cos ๐ฅ + 3 sin ๐ฅ in the
form Rsin(๐ฅ + ๐)
First, let us use the identity ๐ sin(๐ฅ+๐) = ๐ cos(๐)sin(๐ฅ) + ๐ sin(๐)cos(๐ฅ) to rewrite the expression in the desired form.
We can rewrite 4 cos ๐ฅ + 3 sin ๐ฅ as:
4 cos ๐ฅ + 3 sin ๐ฅ = ๐
cos(๐)sin(๐ฅ) + ๐
sin(๐)cos(๐ฅ)
where ๐
and ๐ are constants that we need to determine.
To find ๐
and ๐, we can use the following relationships:
๐
= โ(4^2 + 3^2) = 5
tan ๐ = 3/4
๐ โ 36.87ยฐ
Therefore, we have:
4 cos ๐ฅ + 3 sin ๐ฅ = 5 cos(36.87ยฐ) sin ๐ฅ + 5 sin(36.87ยฐ) cos ๐ฅ
So, the expression in the form Rsin(๐ฅ + ๐) is:
5 sin(๐ฅ + 36.87ยฐ)
To express 4 cos ๐ฅ + 3 sin ๐ฅ in the form Rsin(๐ฅ + ๐), we can use the following steps:
Step 1: Rewrite the expression using the identity: ๐
sin(๐ฅ + ๐) = ๐
(sin ๐ฅ cos ๐ + cos ๐ฅ sin ๐).
Step 2: Rearrange the terms to match the given expression: ๐
(sin ๐ฅ cos ๐ + cos ๐ฅ sin ๐) = ๐
cos ๐ sin ๐ฅ + ๐
sin ๐ cos ๐ฅ.
Step 3: Compare the coefficients of sin ๐ฅ and cos ๐ฅ in the given expression with ๐
sin ๐ and ๐
cos ๐ from Step 2. Equate the coefficients to find ๐
sin ๐ and ๐
cos ๐.
From the given expression, we have:
4 cos ๐ฅ + 3 sin ๐ฅ = ๐
cos ๐ sin ๐ฅ + ๐
sin ๐ cos ๐ฅ.
Comparing the coefficients, we can set up the following equations:
๐
cos ๐ = 4
๐
sin ๐ = 3
Step 4: Solve the equations from Step 3 to find ๐
, ๐.
Dividing the second equation by the first equation, we get:
(๐
sin ๐) / (๐
cos ๐) = 3 / 4
tan ๐ = 3 / 4
Taking the arctan of both sides to solve for ๐:
๐ = arctan(3 / 4)
Substituting the value of ๐ into the first equation, we can solve for ๐
:
๐
cos (arctan(3 / 4)) = 4
Using the identity: cos(arctan(๐ฅ)) = 1 / sqrt(1 + ๐ฅ^2), we can rewrite the equation as:
๐
/ sqrt(1 + (3 / 4)^2) = 4
๐
/ sqrt(1 + 9 / 16) = 4
๐
/ sqrt(25 / 16) = 4
๐
/ (5 / 4) = 4
๐
= 4 * (5 / 4)
๐
= 5
Step 5: Substitute the values of ๐
and ๐ back into the expression ๐
sin(๐ฅ + ๐):
๐
sin(๐ฅ + ๐) = 5sin(๐ฅ + arctan(3 / 4))
So, the expression 4 cos ๐ฅ + 3 sin ๐ฅ can be written in the form 5sin(๐ฅ + arctan(3 / 4)).