Express

4 cos ๐‘ฅ + 3 sin ๐‘ฅ in the
form Rsin(๐‘ฅ + ๐œƒ)

First, let us use the identity ๐‘…sin(๐‘ฅ+๐œƒ) = ๐‘…cos(๐œƒ)sin(๐‘ฅ) + ๐‘…sin(๐œƒ)cos(๐‘ฅ) to rewrite the expression in the desired form.

We can rewrite 4 cos ๐‘ฅ + 3 sin ๐‘ฅ as:

4 cos ๐‘ฅ + 3 sin ๐‘ฅ = ๐‘…cos(๐œƒ)sin(๐‘ฅ) + ๐‘…sin(๐œƒ)cos(๐‘ฅ)

where ๐‘… and ๐œƒ are constants that we need to determine.

To find ๐‘… and ๐œƒ, we can use the following relationships:

๐‘… = โˆš(4^2 + 3^2) = 5

tan ๐œƒ = 3/4

๐œƒ โ‰ˆ 36.87ยฐ

Therefore, we have:

4 cos ๐‘ฅ + 3 sin ๐‘ฅ = 5 cos(36.87ยฐ) sin ๐‘ฅ + 5 sin(36.87ยฐ) cos ๐‘ฅ

So, the expression in the form Rsin(๐‘ฅ + ๐œƒ) is:

5 sin(๐‘ฅ + 36.87ยฐ)

To express 4 cos ๐‘ฅ + 3 sin ๐‘ฅ in the form Rsin(๐‘ฅ + ๐œƒ), we can use the following steps:

Step 1: Rewrite the expression using the identity: ๐‘…sin(๐‘ฅ + ๐œƒ) = ๐‘…(sin ๐‘ฅ cos ๐œƒ + cos ๐‘ฅ sin ๐œƒ).

Step 2: Rearrange the terms to match the given expression: ๐‘…(sin ๐‘ฅ cos ๐œƒ + cos ๐‘ฅ sin ๐œƒ) = ๐‘…cos ๐œƒ sin ๐‘ฅ + ๐‘…sin ๐œƒ cos ๐‘ฅ.

Step 3: Compare the coefficients of sin ๐‘ฅ and cos ๐‘ฅ in the given expression with ๐‘…sin ๐œƒ and ๐‘…cos ๐œƒ from Step 2. Equate the coefficients to find ๐‘…sin ๐œƒ and ๐‘…cos ๐œƒ.

From the given expression, we have:
4 cos ๐‘ฅ + 3 sin ๐‘ฅ = ๐‘…cos ๐œƒ sin ๐‘ฅ + ๐‘…sin ๐œƒ cos ๐‘ฅ.

Comparing the coefficients, we can set up the following equations:
๐‘…cos ๐œƒ = 4
๐‘…sin ๐œƒ = 3

Step 4: Solve the equations from Step 3 to find ๐‘…, ๐œƒ.

Dividing the second equation by the first equation, we get:
(๐‘…sin ๐œƒ) / (๐‘…cos ๐œƒ) = 3 / 4
tan ๐œƒ = 3 / 4

Taking the arctan of both sides to solve for ๐œƒ:
๐œƒ = arctan(3 / 4)

Substituting the value of ๐œƒ into the first equation, we can solve for ๐‘…:
๐‘…cos (arctan(3 / 4)) = 4

Using the identity: cos(arctan(๐‘ฅ)) = 1 / sqrt(1 + ๐‘ฅ^2), we can rewrite the equation as:
๐‘… / sqrt(1 + (3 / 4)^2) = 4
๐‘… / sqrt(1 + 9 / 16) = 4
๐‘… / sqrt(25 / 16) = 4
๐‘… / (5 / 4) = 4
๐‘… = 4 * (5 / 4)
๐‘… = 5

Step 5: Substitute the values of ๐‘… and ๐œƒ back into the expression ๐‘…sin(๐‘ฅ + ๐œƒ):

๐‘…sin(๐‘ฅ + ๐œƒ) = 5sin(๐‘ฅ + arctan(3 / 4))

So, the expression 4 cos ๐‘ฅ + 3 sin ๐‘ฅ can be written in the form 5sin(๐‘ฅ + arctan(3 / 4)).