Private Colleges:

Sample mean = 42.7
sample standard deviation = 6.91
n = 10
51.8 44.2 46.0 32.3 43.0
31.6 45.8 38.8 51.5 42.0

Public Colleges:
sample mean: 22.3
sample standard deviation: 4.53
n = 12
20.3 22.0 28.2 15.6 24.1 28.5
22.8 25.8 18.5 25.6 14.4 21.8

Standard Error = 3.895
Margin of Error = 7.634
Critical value = 1.96
Point Estimate = 20.4 (private - public)

Mean annual cost for private = 20400 more than the mean annual cost for public.

What is the degree of freedom?
and
what is the 95% confidence interval of the difference between the mean annual cost of attending private and public colleges?

The degree of freedom is 20, calculated as (10-1) + (12-1) = 20.

The 95% confidence interval can be calculated using the formula:

(point estimate) +/- (critical value) * (standard error)

Substituting the values given:

20.4 +/- 1.96 * 3.895

The upper bound is:

20.4 + 7.634 = 28.034

The lower bound is:

20.4 - 7.634 = 12.766

Therefore, the 95% confidence interval of the difference between the mean annual cost of attending private and public colleges is (12.766, 28.034).

To determine the degree of freedom for this sample, we need to know the sample sizes for both the private and public colleges. Could you please provide that information?