Given that

(๐‘ฅ โˆ’ ๐ด)2 + ๐ต = ๐‘ฅ2 โˆ’ 10๐‘ฅ +
29, ๐‘“๐‘–๐‘›๐‘‘ ๐‘กโ„Ž๐‘’ ๐‘ฃ๐‘Ž๐‘™๐‘ข๐‘’ ๐‘œ๐‘“ ๐ด + ๐ต
A. -9
B.-1
C.8
D. 9

Expanding the left-hand side of the given equation, we have:

(๐‘ฅ โˆ’ ๐ด)2 + ๐ต = ๐‘ฅ2 โˆ’ 2๐‘ฅ๐ด + ๐ด2 + ๐ต

Setting this equal to ๐‘ฅ2 โˆ’ 10๐‘ฅ + 29, we get:

๐‘ฅ2 โˆ’ 2๐‘ฅ๐ด + ๐ด2 + ๐ต = ๐‘ฅ2 โˆ’ 10๐‘ฅ + 29

Simplifying and rearranging, we get:

2๐‘ฅ๐ด โˆ’ ๐ด2 โˆ’ 10๐‘ฅ + ๐ต โˆ’ 29 = 0

This is a quadratic equation in ๐‘ฅ, with coefficients that depend on ๐ด and ๐ต. We can use the quadratic formula to find the solutions for ๐‘ฅ:

๐‘ฅ = [10 ยฑ sqrt(100 - 4(2๐ด - ๐ต + 29 - ๐ด2))]/(4)

Simplifying under the square root, we get:

100 - 8๐ด + 2๐ต - 4๐ด2 - 116 = -4(๐ด - 4)2

Substituting this back into the formula for ๐‘ฅ, we get:

๐‘ฅ = [10 ยฑ 2sqrt(-4(๐ด - 4)2)]/4 = 5 ยฑ i(๐ด - 4)/2

The real part of these solutions is ๐‘ฅ = 5, so we need to choose the value of ๐ด and ๐ต that make the imaginary part vanish. This happens when:

๐ด - 4 = 0, so ๐ด = 4

-๐ด2 + ๐ต - 29 = 0, so ๐ต = ๐ด2 - 29 = -13

Therefore, the value of ๐‘“(๐ด + ๐ต) is:

๐‘“(4 + (-13)) = ๐‘“(-9)

Substituting into the original equation, we get:

(๐‘ฅ โˆ’ 4)2 - 13 = ๐‘ฅ2 โˆ’ 10๐‘ฅ + 29

Simplifying and rearranging, we get:

๐‘ฅ2 - 12๐‘ฅ + 56 = 0

Factoring, we get:

(๐‘ฅ - 4)(๐‘ฅ - 8) = 0

Therefore, the solutions for ๐‘ฅ are ๐‘ฅ = 4 and ๐‘ฅ = 8. The value we are looking for is the negative of the sum of these solutions:

- (4 + 8) = -12

Therefore, the answer is (E) -12.

To find the value of A + B, we need to compare the expanded form of the given equation with the standard form of a quadratic equation, which is ax^2 + bx + c.

Given equation: (x - A)^2 + B = x^2 - 10x + 29

Comparing all the terms:

(x - A)^2 + B = x^2 - 10x + 29

Expanding (x - A)^2:

x^2 - 2Ax + A^2 + B = x^2 - 10x + 29

Comparing like terms:

-2Ax + A^2 + B = -10x + 29

Comparing the x term on both sides, we get:

-2A = -10

Solving for A:

A = -10 / -2 = 5

Now, substituting the value of A back into the equation, we get:

-10x + A^2 + B = -10x + 29

A^2 + B = 29

Substituting the value of A (5) into the equation:

5^2 + B = 29

25 + B = 29

Subtracting 25 from both sides:

B = 4

Now, calculating A + B:

A + B = 5 + 4 = 9

Therefore, the value of A + B is 9. So, the correct answer is D. 9.