A boat of mass 350kg starts off from rest and travels a distance of 60m in 10s at constant acceleration, find the net force acting on the boat.
We can use the equation:
distance = (initial velocity)(time) + (1/2)(acceleration)(time)^2
Rearranging and plugging in the given values, we get:
(1/2)(acceleration)(time)^2 = distance - (initial velocity)(time)
(1/2)(acceleration)(10s)^2 = 60m - 0m/s * 10s
acceleration = 1.2 m/s^2
Now, we can use Newton's second law:
net force = mass x acceleration
net force = 350kg x 1.2 m/s^2
net force = 420 N
Therefore, the net force acting on the boat is 420 N.
To find the net force acting on the boat, we can use Newton's second law of motion, which states that the net force (F_net) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a).
First, we need to find the acceleration of the boat. The formula to calculate acceleration is:
a = (final velocity - initial velocity) / time
In this case, the boat starts from rest, so its initial velocity (u) is 0 m/s. The final velocity (v) can be calculated using the following formula:
v = u + at
where u is the initial velocity, a is acceleration, and t is time. Rearranging the formula, we get:
v = u + at
at = v - u
a = (v - u) / t
Given that the distance covered (s) is 60 m and the time (t) is 10 s, we can use the formula:
s = ut + (1/2)at^2
Rearranging the formula, we get:
2s = 2ut + at^2
2s = 0 + at^2 (since u=0)
at^2 = 2s
a = (2s) / t^2
Substituting the given values, we have:
a = (2 * 60) / (10^2)
a = 120 / 100
a = 1.2 m/s^2
Now we can calculate the net force:
F_net = m * a
F_net = 350 kg * 1.2 m/s^2
F_net = 420 N
Therefore, the net force acting on the boat is 420 N.