A women is 6 years younger to her husband and he is 5 times as old as his daughter. If daughter was 7 years old 2 years back, what is present age of women?
If the daughter was 7 years old 2 years back, she is currently 9 years old.
Let's denote the current age of the husband as H and the current age of the wife as W.
From the first statement, we know that:
W = H - 6
From the second statement, we know that:
H = 5D
Where D is the current age of the daughter. Since we know that the daughter is currently 9 years old, we can substitute this value into the equation above:
H = 5(9)
H = 45
Using this value of H, we can use the first equation to solve for W:
W = 45 - 6
W = 39
Therefore, the current age of the woman is 39.
Let's solve this step by step:
Step 1: Let's assume the present age of the daughter is D years.
Step 2: According to the information given, "he is 5 times as old as his daughter," so the present age of the husband (H) would be 5D years.
Step 3: According to the information given, "A women is 6 years younger than her husband," so the present age of the wife (W) would be H - 6 years.
Step 4: We know that two years back, the daughter was 7 years old. This means that 2 years ago, D - 2 = 7.
Step 5: From Step 4, we can deduce that the present age of the daughter D = 7 + 2 = 9 years.
Step 6: Substituting the value of D in Step 5 into Step 2, we have H = 5 * 9 = 45 years.
Step 7: Substituting the value of H in Step 6 into Step 3, we have W = 45 - 6 = 39 years.
Therefore, the present age of the woman is 39 years.