The force of 0.8n streach and elastic spring by 2cm .find the elastic constant of a spring
The elastic constant of a spring can be found using the formula:
k = F / x
where k is the elastic constant, F is the force applied, and x is the displacement.
In this case, the force is 0.8N and the displacement is 2cm (or 0.02m). Therefore, the elastic constant would be:
k = 0.8N / 0.02m
k = 40 N/m
The elastic constant of the spring is 40 N/m.
To find the elastic constant of a spring, also known as the spring constant or stiffness constant (k), we can use Hooke's Law formula:
F = k * x
where:
F is the force applied to the spring,
k is the elastic constant,
x is the displacement or stretch of the spring.
In this case, the force applied (F) is 0.8N, and the displacement (x) is 2cm (which we will convert to meters later).
Let's solve for k:
k = F / x
First, we need to convert the displacement from centimeters to meters:
1 meter = 100 centimeters
Therefore, 2 centimeters = 2 / 100 = 0.02 meters
Now, we can substitute the values into the formula:
k = 0.8N / 0.02m
k = 40 N/m
So, the elastic constant of the spring is 40 N/m.