Seth has baseball tryouts at school at 3:30 p.m. He needs to get his glove from home.
It takes him 15 minutes to walk home and 15 minutes to walk back to school.
At home, he will take 10 minutes to eat a snack.
What time does Seth need to leave school so that he will get back in time for tryouts?
Drag the numbers to order the steps to solve the problem.
123
It takes Seth 15 minutes to walk to school from home, so I subtract 15 minutes from 3:05 p.m. to get 2:50 p.m.
It takes Seth 15 minutes to walk from school to home, so I subtract 15 minutes from 3:30 p.m. to get 3:15 p.m.
It takes Seth 10 minutes to eat his snack at home, so I subtract 10 minutes from 3:15 p.m. to get 3:05 p.m.
1. Determine the time Seth needs to be back at school for tryouts (3:30 p.m.).
2. Calculate the time it will take Seth to walk home and back to school (15 minutes each way).
3. Subtract the time it takes to walk from school to home from the time of tryouts (3:30 p.m. - 15 minutes = 3:15 p.m.).
4. Subtract the time it takes to eat a snack at home from the time it takes to walk from school to home (3:15 p.m. - 10 minutes = 3:05 p.m.).
5. Seth needs to leave school before 3:05 p.m. so he can get home, eat a snack, and get back to school in time for tryouts.
1. It takes Seth 10 minutes to eat his snack at home, so I subtract 10 minutes from 3:30 p.m. to get 3:20 p.m.
2. It takes Seth 15 minutes to walk from school to home, so I subtract 15 minutes from 3:20 p.m. to get 3:05 p.m.
3. It takes Seth 15 minutes to walk to school from home, so I subtract 15 minutes from 3:05 p.m. to get 2:50 p.m.
Therefore, Seth needs to leave school at 2:50 p.m. to get back in time for tryouts.