What is the molarity of a solution containing 11.522 grams of KOH in enough water to make 350ML of solution?
First, we need to calculate the number of moles of KOH in the solution:
moles of KOH = mass / molar mass
molar mass of KOH = 39.1 g/mol (K) + 16.0 g/mol (O) + 1.0 g/mol (H) = 56.1 g/mol
moles of KOH = 11.522 g / 56.1 g/mol = 0.205 moles
Next, we need to calculate the molarity of the solution:
molarity = moles of solute / liters of solution
since we have 350 mL of solution, we need to convert to liters by dividing by 1000:
molarity = 0.205 moles / 0.35 liters = 0.586 M
Therefore, the molarity of the solution containing 11.522 grams of KOH in enough water to make 350 mL of solution is 0.586 M.
To calculate the molarity of a solution, you need to know the number of moles of the solute and the volume of the solution in liters.
First, determine the number of moles of KOH using its molar mass:
Molar mass of KOH (K = 39.10 g/mol, O = 16.00 g/mol, H = 1.01 g/mol):
= 39.10 g/mol + 16.00 g/mol + 1.01 g/mol
= 56.11 g/mol
Number of moles of KOH = (mass of KOH) / (molar mass of KOH)
= 11.522 g / 56.11 g/mol
= 0.2053 mol
Next, convert the volume of the solution from milliliters to liters:
Volume of solution = 350 mL = 350/1000 L
= 0.350 L
Finally, calculate the molarity (M) using the formula:
Molarity = (moles of solute) / (volume of solution in liters)
= 0.2053 mol / 0.350 L
= 0.586 M
Therefore, the molarity of the solution containing 11.522 grams of KOH in enough water to make 350 mL of solution is approximately 0.586 M.